What is the equation of the line that passes through the point (-6,-6)and has a slope of -\frac{1}{3}− ?

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  y +6 = (-1/3)(x +6)

Step-by-step explanation:

Given a point and a slope, it is appropriate to use the point-slope form to represent the equation:

  y -k = m(x -h) . . . . . line with slope m through point (h, k)

For your point and slope, the equation is ...

  y -(-6) = -1/3(x -(-6))

  y +6 = -1/3(x +6)

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Of course, this can be rearranged to whatever form you need.

  y = -1/3x -8 . . . . slope-intercept form

  x +3y = -24 . . . . standard form

answer: it's upside down and i can't read it

step-by-step explanation: