PLEASE HELP I NEED THIS ASAP In this activity, you will rearrange and solve a rational equation and find and use the inverse of a rational equation.

As we’ve seen, for a circuit with two resistors arranged in parallel, we can calculate the total resistance in the circuit, RT , in ohms, with this equation.

1.Rewrite the equation to represent the resistance of resistor 2, R2 , in terms of RT and R1.
A. R2=RTR1/R1-1
B. R2= R1 + R2/RT R1
C. R2=RT - R1/RTR1
D. R2= RT R1/R1-RT
-
The total resistance in a circuit with two parallel resistors is 2 ohms and R1 is 6 ohms.
Using the equation for R2, in terms of RT and R1, what is R2?
R2 is ? ohms
-
2.Lightbulbs act as resistors. Janine is building a circuit that contains two lightbulbs in parallel. One of the lightbulbs has a resistance of 120 ohms, but the resistance of the second lightbulb is unknown. She models the total resistance in the circuit, t, with this equation, in which r represents the resistance of the second lightbulb.
t=120r/r+120
Find the inverse of Janine’s equation.
-
Janine determines that the total resistance in her circuit is 80 ohms. Using the inverse equation modeling this situation, find the resistance of the second lightbulb.

The resistance of the second lightbulb is ? ohms

Just Did This Assignment:

1. Rewrite the equation to represent the resistance of resistor 2, R2, in terms of RT and R1

:R2=RTR1/R1−RT (D)

2. The total resistance in a circuit with two parallel resistors is 2 ohms and R1 is 6 ohms.  Using the equation for R2, in terms of RT and R1, what is R2?

:3

3. Lightbulbs act as resistors. Janine is building a circuit that contains two lightbulbs in parallel. One of the lightbulbs has a resistance of 120 ohms, but the resistance of the second lightbulb is unknown. She models the total resistance in the circuit, t, with this equation, in which r represents the resistance of the second lightbulb.

t=120rr+120

Find the inverse of Janine’s equation.

:r=120t/120-t

4. Janine determines that the total resistance in her circuit is 80 ohms. Using the inverse equation modeling this situation, find the resistance of the second lightbulb.

:The resistance of the second lightbulb is  240  ohms.

the answer is a

step-by-step explanation:

39.00 x 24 = total installment price

carrying installment price - cash price

needed to save the .00/

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.