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Mathematics, 15.12.2020 23:50, Jharsh525
A relay race is 1 3 4 miles long. Each relay team has 4 runners. If each runner runs the same distance in the race, how far will each runner run? Choose the correct answer. StartFraction 7 Over 4 EndFraction times StartFraction 4 Over 1 EndFraction = 7, so each runner runs 7 miles. StartFraction 7 Over 4 EndFraction times StartFraction 4 Over 1 EndFraction = 28, so each runner runs 28 miles. StartFraction 7 Over 4 EndFraction times StartFraction 4 Over 1 EndFraction = StartFraction 7 over 16 EndFraction, so each runner runs StartFraction 7 Over 16 EndFraction miles. StartFraction 7 Over 4 EndFraction times StartFraction 4 Over 1 EndFraction = StartFraction 7 over 8 EndFraction, so each runner runs StartFraction 7 Over 8 EndFractionmiles
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Prove (a) cosh2(x) ā sinh2(x) = 1 and (b) 1 ā tanh 2(x) = sech 2(x). solution (a) cosh2(x) ā sinh2(x) = ex + eāx 2 2 ā 2 = e2x + 2 + eā2x 4 ā = 4 = . (b) we start with the identity proved in part (a): cosh2(x) ā sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 ā sinh2(x) cosh2(x) = 1 or 1 ā tanh 2(x) = .
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A relay race is 1 3 4 miles long. Each relay team has 4 runners. If each runner runs the same distan...
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