Use the coordinates of the labeled point to find the point slope equation of the line.

B

Step-by-step explanation:

Here, we want to find the point-slope equation of the line

We start by getting the y-intercept of the line which is y = 3

The general equation of a straight line is;

y = mx + b

where b is the y-intercept

So, we have;

y = mx + 3

Now, to get m , we insert the point given on the like which is (2,-5)

x = 2 and y = -5

-5 = 2m + 3

-8 = 2m

m = -8/2

m = -4

So the equation of the line is;

y = -4x + 3

This is same as option B

4

step-by-step explanation: