A model for a company’s revenue from selling a software package is R(p)=-2.5p^2+600p

Complete question is;

A model for a company's revenue from selling a software package is R = -2.5p² + 500p, where p is the price in dollars of the software. What price will maximize revenue? Find the maximum revenue.

Price to maximize revenue = $100

Maximum revenue = $25000

Step-by-step explanation:

We are told that:

R = -2.5p² + 500p, where p is the price in dollars of the software.

The maximum revenue will occur at the vertex of the parabola.

Thus, the price at this vertex is;

p = -b/2a

Where a = - 2.5 and b = 500

Thus:

p = -500/(2 × -2.5)

p = -500/-5

p = 100 in dollars

Maximum revenue at this price is;

R(100) = -2.5(100)² + 500(100)

R(100) = -25000 + 50000

R(100) = $25000

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐