Linda left home and drove for 2 hours. She stopped for lunch then drove for another 3 hours at a rate that is 10 mph higher than the rate before she had lunch. If the total distance Linda traveled is 250 miles, what was the rate before lunch

44 mph

Step-by-step explanation:

Given that:

Before lunch :

Time taken = 2hrs ; at speed = x mph

After lunch :

Time taken = 3hrs ; at speed = x + 10 mph

Total distance covered = 250 miles :

Distance = speed * time

(2 * x) + (3 * (x + 10)) = 250

2x + 3x + 30 = 250

5x + 30 = 250

5x = 250 - 30

5x = 220

x = 220/ 5

x = 44 mph

Rate before lunch is 44mph

step-by-step explanation:

left be aligning the decimal points is required to not required see the number of digits to the right