g According to government data, 25% of employed women have never been married. If 10 employed women are selected at random, what is the probability that two or fewer of them have never been married

The probability is 0.5263

Step-by-step explanation:

Probability of employed women being unmarried = 25% = 0.25 ( let this be p)

Probability of employed women ever being married = 1-0.25 = 0.75 (let this be q)

Now, we want to calculate the probability that two or less have never been married

We can use the Bernoulli approximation of the Binomial distribution here;

In this case, we have three cases

We have cases of;

Exactly two + Exactly one + None

For exactly two;

10 C 2 0.25^2 0.75^8 = 0.282

For exactly one

10 C 1 0.25^1 0.75^9 = 0.188

For none

10C 0 0.25^0 0.75^10 = 0.0563

Adding these 3 to get the probability of two or fewer, we have;

0.0563 + 0.188 + 0.282 = 0.5263

child does not get an education so she can use the molla on junk

i believe your answer is 99.7% of 7-year-old children are between 46.6 inches and 49.5 inches tall.