Mathematics, 15.12.2020 14:00, MK100

2. A spider can walk at a certain speed and run at another speed. If she walks for 10 seconds and runs for 9
seconds, she travels 85m. If she walks for 30 seconds and
runs for 2 seconds, she travels 130m. Find her speeds of
walking and running.

Answers: 1

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Answers

answered: kristine2424

The answer is below

Step-by-step explanation:

Speed is the ratio of distance covered to the time taken. Speed is given by the formula:

speed = distance / time.

Let us assume the spider walking speed is x and its running speed is y.

If the spider walks for 10 seconds and runs for 9 seconds, she travels 85m. distance = speed * time, hence:

Total distance = distance covered walking + distance covered running

10x + 9y = 85 (1)

Also if she walks for 30 seconds and runs for 2 seconds, she travels 130m. Hence:

30x + 2y = 130 (2)

Solving equation 1 and 2 simultaneously by mutiplying equation 1 by 3 and subtracting equation 2 from the result:

25y = 125

y =5 m/s

Put y = 5 in eqn. 2

30x + 2(5) = 130

30x = 120

x = 4 m/s

The spider walks at 4 m/s and runs at 5 m/s

answered: Guest

No solution : there is no number of boxes that she bought

answered: Guest

x= 1

step-by-step explanation: convert 5\frac{11}{12}5

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{5\times 12+11}{12}3.25+0.5x+1

5×12+11

2 simplify 5\times 125×12 to 6060

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{60+11}{12}3.25+0.5x+1

60+11

3 simplify 60+1160+11 to 7171

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{71}{12}3.25+0.5x+1

4 simplify \frac{5}{6}x

x to \frac{5x}{6}

3.25+0.5x+1\frac{1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+1

5 convert 1\frac{1}{3}1

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+\frac{1\times 3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

1×3+1

6 simplify 1\times 31×3 to 33

3.25+0.5x+\frac{3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

3+1

7 simplify 3+13+1 to 44

3.25+0.5x+\frac{4}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

8 simplify 3.25+0.5x+\frac{4}{3}+\frac{5x}{6}3.25+0.5x+

to \frac{13.75}{3}+\frac{4x}{3}

13.75

\frac{13.75}{3}+\frac{4x}{3}=\frac{71}{12}

13.75

9 simplify \frac{13.75}{3}

13.75

to 4.5833334.583333

4.583333+\frac{4x}{3}=\frac{71}{12}4.583333+

10 subtract 4.5833334.583333 from both sides

\frac{4x}{3}=\frac{71}{12}-4.583333

−4.583333

11 simplify \frac{71}{12}-4.583333

−4.583333 to \frac{4}{3}

\frac{4x}{3}=\frac{4}{3}

12 multiply both sides by 33

4x=\frac{4}{3}\times 34x=

×3

13 simplify \frac{4}{3}\times 3

×3 to \frac{12}{3}

4x=\frac{12}{3}4x=

14 simplify \frac{12}{3}

to 44

4x=44x=4

15 divide both sides by 44

x=1

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Other tasks in the category: Mathematics More task

2. A spider can walk at a certain speed and run at another speed. If she walks for 10 seconds and runs for 9 seconds, she travels 85m. If she walks for 30 seconds and runs for 2 seconds, she travels 130m. Find her speeds of walking and running.

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Questions in other subjects:

2. A spider can walk at a certain speed and run at another speed. If she walks for 10 seconds and runs for 9
seconds, she travels 85m. If she walks for 30 seconds and
runs for 2 seconds, she travels 130m. Find her speeds of
walking and running.