A bag contains three red counters, four green counters, two yellow counters and one white counter. Two counters are drawn from the bag one after the other, without being replaced.
Calculate:
a P(two red counters)
b P(two green counters)
c P(two yellow counters)
d P(white and then red)
e P(white or yellow, in either order but not both)
f P(white or red, in either order but not both).
g What is the probability of drawing a white or yellow counter first and then any
colour second?

idk

step-by-step explanation:

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

answer:

idk

step-by-step explanation:

160 cm

step-by-step explanation:

you have to add all the sides together