2a+3r+1.5p=29.75 (1)
a+r+p=13.50 (2)
a+3r+4p=29.00 (3)
Eliminate a by multi...
Mathematics, 14.12.2020 20:40, dorothybean
2a+3r+1.5p=29.75 (1)
a+r+p=13.50 (2)
a+3r+4p=29.00 (3)
Eliminate a by multiplying equation (2) by -1 and adding it to equation (3).
What is the resulting equation?
4r + 5p = 42.50
2r + 3p = 15.50
2r + 3p = 42.50
Answers: 2
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