Line g is dilated by a scale factor of 3 from the origin to create line g'. Where are points E' and F' located after dilation, and how are lines g and g' related? The locations of E' and F' are E' (−4, 0) and F' (0, 2), and lines g and g' are the same line. The locations of E' and F' are E' (−2, 0) and F' (0, 1), and lines g and g' intersect at point F. The locations of E' and F' are E' (−1, 0) and F' (0, 0), and lines g and g' are not related. The locations of E' and F' are E' (−12, 0) and F' (0, 6), and lines g and g' are parallel.

answer: 177/8

step-by-step explanation:

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube

step-by-step explanation:

we have

using a graphing tool

see the attached figure

this is a quadratic equation (vertical parabola) open up

the vertex is a > vertex

the domain of the function is all real > interval (-∞,∞)

the range of the function is the > [-6.125,∞)

the function has two x->   and

the function is increasing over the > (0.25,∞)

the function is decreasing over the > (-∞,0.25)