The sum of two numbers is 96 the larger number is nine less than four times the smaller number find both numbers

21 and 96

Step-by-step explanation:

Let x and y be the two numbers such that x>y.

As the sum of both the numbers is 96.

x+y=96...(i)

As the larger number is nine less than four times the smaller number,

So, x=4y-9

From equation (i),

4y-9+y=96

5y=96+9=105

So, y=105/5=21

By using equation (i),

x=96-y=96-21=75

Hence, both the numbers are 21 and 96.

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

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step-by-step explanation: