A mixture of paint calls for 1/3 cups of red paint and 3/4 cups of yellow paint. If there were 4 cups of red paint added to the mixture, how many cups of yellow paint would need to be added to keep a constant rate of proportionality? (Hint: You can use your answer from the first question to help you solve this!)

9 cups of yellow paint

Step-by-step explanation:

A mixture of paint calls for 1/3 cups of red paint and 3/4 cups of yellow paint.

From the above question

1/3 cups of red paint = 3/4 cups of yellow paint

1 cup of red paint = x cups of yellow paint

Cross Multiply

1/3 × x = 3/4 × 1

x = 3/4 ÷ 1/3

x = 3/4 × 3/1

x = 9/4

x = 2 1/4 cups of yellow paint

Hence, 1 cups of red paint requires 2 1/4 cups of yellow paint

If there were 4 cups of red paint added to the mixture, how many cups of yellow paint would need to be added to keep a constant rate of proportionality?

1 cups of red paint = 2 1/4 cups of yellow paint

4 cups of red paint = x cups of yellow paint

Cross Multiply

x cups of yellow paint = 4 × 2 1/4 cups of yellow paint

= 4 × 9/4 cups of yellow paint

= 9 cups of yellow paint

Therefore, 4 cups of red paint requires 9 cups of yellow paint

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

b) well because you get well