The graph of g(x) = 3|x|+ 4 maps a person’s path from their house to school, and their path from school to a friend’s house. At what point is the school located?

I think the school is located at (0,4).

Step-by-step explanation:

I graphed the equation in my graphing calculator and it came up with a kind of v shaped graph. If you look at the question and see that we first house to school, that would probably mean from the left side of the graph to the center (0,4). Then we go from school to friend's house, so it must be from the center to the right side of the graph. Therefore, the school must be the y intercept (0,4) as that is the center of the graph.

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true

x^3-4x^2+3x-2/x^2+1

step-by-step explanation:

factor the numerator and denominator and cancel the common factors