The difference between two numbers is 10 and their sum is four times the smaller number.
Find the two numbers.

x = 10

y = 5

Step-by-step explanation:

Let the two numbers be x and y

Difference between the two is 10

x-y = 10

Sum;

x+ y is four times the smallest number

Let the smaller number be y

x+ y = 4y

Subtracting equation ii from i

-2y = 10 -4y

4y-2y = 10

2y = 10

y = 10/2

y = 5

Recall;

x-y = 10

x = 10 + y

x = 10 + 5 = 15

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

answer: 177/8

step-by-step explanation: