The standard normal curve shown below models the population distribution of a random variable What proportion of the values in the population does
not ie between the two zscores indicated on the diagram?
OA 02881
OB. 0.3102
OC. 03064
OD. 0.3175
OE 0.2933

D

Step-by-step explanation:

Here, we want to get the proportion that lies outside the given shown z-scores

Mathematically, that will be:

1 - proportion lying between the two z-scores

The probability lying between the two z-scores can be calculated using the normal distribution table

That will be;

P(-1.25 < x < 0.80)

From the table, this is;

0.68249

So the proportion lying outside will be;

1-0.68249 = 0.31751

This is approximately 0.3175

do i do it on a graph?

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3