Brandon and his children went into a bakery and where they sell donuts for $1.25 each and cookies for $0.25 each. Brandon has $5.50 to spend and must buy a minimum of 10 donuts and cookies altogether. If Brandon decided to buy 2 cookies, determine the maximum number of donuts that he could buy. If there are no possible solutions, submit an empty answer.

he can buy four donuts

Step-by-step explanation:

He bought two cookies which is .50 cents

Subtract .50 cent from the total amount which is $5

Divide that by 1.25

I got 4

for the first question it would be the second answer for the second question it would be the third answer and for the third question it would be the first answer

step-by-step explanation:

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages