Write the equation in slope-intercept form for the line that passes through points (-1,6) and (3,-2)

Given that the line passes through two points (-1,2) and (6,3)

Slope of the line passing through (x1,y1) and (x2,y2) is

Hence slope of our line =

(3-2)/(6+1) = 1/7

So in slope intercept form the equation would be

y = 1/7 x +C

to find C

Since (-1,2) lies on the line substitute these in the line equation

2 = 1/7(-1)+c

C = 2+1/7 = 15/7

Hence equation in slope intercept form is

Step-by-step explanation:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this