ABC, the measure of C=90, the measure of A= 49, and BC=5.1 feet. Find the length of AB to the nearest tenth of a foot.

my acc plz

step-by-step explanation:

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

what is the information provided?

step-by-step explanation:

if e is the midpoint of bd, then bd is 14.

step-by-step explanation: