The data in the table are given along with two possible lines of fit. Calculate the residuals for both lines of fit and then find the sum of the squared residuals. Identify the lesser sum and the line with better fit.
Round your answers to the nearest hundredth.
X2 46
8
y 5 9 10 12
y = 3x + 4
y = 3x + 3.8
Residuals:
(actual)
y predicted by
y - 3x + 4
residual for
y = 3x + 4
y predicted by
y = 3x + 3.8
residual for
y - 3x + 3.8
5
10
5
9.8
4.8
No
9
16
7
15.8
6.8
10
22
12
21.8
11.8
8
12
28
16
27.8
15.8
For the 1st equation, y= 3x + 4 the sum of the squared residuals is
For the 2nd equation, y= 3x + 3.8, the sum of the squared residuals is
The sum of the squared residuals for the (1st/2nd)
equation is a better fit.
Blank 1:
Blank 2:
Blank 3: