Solve the system of equation by the substitution method
y=5x+1
2y-6x=10

x=2 and y=11

Step-by-step explanation:

Okay so subtitution method

y=5x+1

2y-6x=10

Plug in the y

2(5x+1

)-6x=10

10x+2-6x=10

4x+2=10

4x=8

x=2

now plug in for y

lets use first equation

y=5(2)+1

y=10+1

y=11

Brainliest please.

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.