What are the coordinates of the vertex of the graph of the function y = –x² + 6x –11?

The solution to your problem is as follows:

y = –x² + 6x –11 

same objective : f(x) = a(x - h)^2 + k as V(h,k) as vertex 

so here: 

y = –x² + 6x – 11 
y = –(x² - 2*3x + 3^2) – 2 
y = - (x - 3)^2 - 2 > h = 3 and k = -2 

Therefore, the coordinates of the vertex for the graph is (3,-2).

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