If f'(x) = 2/x and f(sqrt of e) =5, then f(e) =?

F(x) = 2ln(x) + c [integral of 1/x is ln x] 
f(e^(1/2)) = 2ln(e^(1/2)) + c = 5 
2(1/2) + c = 5 [ln(e^a) = a] 
1 + c = 5 
c = 4 

So: 
f(e) = 2ln(e) + 4 = 2 + 4 = 6 

Answer is 6. 

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Im not that good with division but i think 5 is -6but dont quote me on thatim not the best in division but thats my answer