Find the derivation of y=sin (2x2 + 3x-4) a. -cos (4x +3) b. -(6x2+3) cos (2x3+3x-4) c. Cos (2x3+3x-4)
d. (6x3+3) cos (2x3+3)

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)