Plz help me find the answer!

x=50°

Angle at A=108°

Step-by-step explanation:

If the triangle ABC is isosceles,then <ABC=<ACB=65°

We can now use angle properties to find <BAC

<BAC+65+65=180°

<BAC=180°-130=50°

Since line AB and CD are parallel,line AC is a transversal line which means <BAC=<ACD=x=50°

Therefore x=50°

For the parallelogram,

opposite interior angles are equal so <BAD=<BCD and <ABC=<ADC

3x+3x+2x+2x=360°

10x=360°

x=360°/10=36°

The angle at a=3x=3×36°=108°