In an AP, the ratio of the 7th term to the 10th term is -1. If the 16th term is -15, what is the 3rd term?

The 3rd term is 11

Step-by-step explanation:

The given parameters for the Arithmetic Progression, AP, are;

The ratio of the 7th term to the 10th term = (a + 6·d)/(a + 9·d) = -1

The 16th term = -15 = a + 15·d

The 3rd term= a + 2·d

From the 7th to the 10th term ratio, we have;

a + 6·d = -a - 9·d

2·a = -15·d

-2·a = 15·d...(1)

From the 16th term of the AP, we have;

-15 = a + 15·d =  a + -2·a = -a

a = 15

From equation (1), -2·a = 15·d, we have;

-2·a = -2 × 15 = 15·d

15·d = -2 × 15

d = -2 × 15/15 = -2

d = -2

The 3rd term = a + 2·d = 15 + 2 × -2 = 11

∴ The 3rd term = 11

stops on an even number.

answer: a video game has three difficulty levels: easy, medium, and expert. the game's scoring works in such a way that a player has to score a fixed number of points to advance to the next level, and then the scoring starts over. the total score needed to clear all three difficulty levels is 7,500. two times the number of points needed to clear the easy level is 500 more than the number of points needed to clear the medium level. twice the number of points needed to clear the medium difficulty level is 1,500 more than the number of points needed to clear the expert level. if x, y, and z represent the easy, medium, and expert levels, respectively, and a is the coefficient matrix of the system of equations modeling this situation, identify the inverse matrix, a-1, and the solution matrix, x, of the system of equations.

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