Mathematics
Mathematics, 12.12.2020 16:50, ghughes665

Jamaal converted the following conic equation from general form to standard form. amaal converted the following conic equation from general form to standard form.

4x2 + 4y2 – 16x + 24y – 12 = 0

4x2 – 16x + 4y2 + 24y = 12

4(x2 – 4x) + 4(y2 + 6y) = 12

4(x2 – 4x + 4) + 4(y2 + 6y + 9) = 12 + 4 + 9

4(x – 2)2 + 4(y + 3)2 = 25

Jamaal identifies the center of the circle as

(2, –3) and the radius as r = Five-halves.

What error, if any, did Jamaal make ?

Jamaal misidentified the center. The center should be at the point (–2, 3).
Jamaal did not complete the square correctly; he should have added 16 and 36 inside the parentheses in step 4. The radius is r = StartRoot 55 EndRoot.
Jamaal added 4 and 9 to the right hand side in step 4; he should have added 16 and 36. The radius is r = 8.
Jamaal did not make an error.

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