Mathematics, 12.12.2020 16:50, zachcochran2007

Amaal converted the following conic equation from general form to standard form. 4x2 + 4y2 – 16x + 24y – 12 = 0

4x2 – 16x + 4y2 + 24y = 12

4(x2 – 4x) + 4(y2 + 6y) = 12

4(x2 – 4x + 4) + 4(y2 + 6y + 9) = 12 + 4 + 9

4(x – 2)2 + 4(y + 3)2 = 25

Jamaal identifies the center of the circle as

(2, –3) and the radius as r = Five-halves.

Amaal converted the following conic equation from general form to standard form.

4x2 + 4y2 – 16x

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Amaal converted the following conic equation from general form to standard form. 4x2 + 4y2 – 16x +...