If 4-3(2-x)<10+x what is the greatest possible integer value of x?

4-3(2-x) < 10+x

4 -6 +3x< 10 + x

-2 +3x< 10 +x

2x< 12

x<6

↣ First we solve the Inequality.

    ↣ Distribute -3 in (2-x) for easier in solving.

Thus, the answer is x < 6.

↣ Therefore, the greatest possible Integer value of x is 5.

answer: 4 meters

step-by-step explanation: to you understand 2/3 better you can do 1 divided by 3 = . then multiply that by the 2 which is .66666666666666667 then you would do 6 x .66666666666666667 which is 4.      

hope this .