Write an equation of the line that passes through (-4,3) and (0,6
)

y=¾+8

Step-by-step explanation:

Using the approach y-y1=m(x-x1),where m is the slope defined by ∆y/∆x

So ∆y/∆x=y2-y1/x2-x1

m=6-3/0-(-4)

m=¾

Now plug in m=¾ into the approach and simplify

y-3=¾(x-(-4))

y-3=¾(x+4) Multiply through by 4

4y-12=3x+12 Transpose it for y

4y=3x+12+12

4y=3x+24 divide through by 4

y=¾+8

for the first question it would be the second answer for the second question it would be the third answer and for the third question it would be the first answer

step-by-step explanation:

answer: just subtact the units and then add the non negative : happy to

step-by-step explanation: