Let the random variable X represent the number of pets owned by randomly chosen US households. The table shows the probability distribution if the few households that own more than six pets is ignored. A 2-column table with 7 rows. Column 1 is labeled number of pets with entries 0, 1, 2, 3, 4, 5, 6. Column 2 is labeled Probability with entries 0.15, 0.35, 0.20, 0.15, 0.10, 0.025, 0.025.

What is the probability that a randomly selected US household owns exactly three pets?

0.025
0.05
0.10
0.15
0.20

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

b. x- 48 =120

step-by-step explanation:

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,