How will the solution of the system y > 2x + 2 and y< B 2x + } change if the inequality sign on both inequalities is reversed to y < 2x+ and y2x+12

your welcome haha, this is the best place to find answers

step-by-step explanation:

it will be a cylinder. with a diameter of 8 and 4 single pieces high

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

t

step-by-step explanation:

ever thing time 1 is a multiply by 1 it get