Justin has 20 pencils 25 erasers and 40 paper clips. He organizes them into groups with the same number of items in each group. All the items in a group will be the same type. How many items can he put in each group?

Justin wants to divide up pencils, erasers and paper clips into equal quantities. Presumably, if he hands these out to people, the recipients will have the same amount of some pencils, some erasers, and some paper clips.

The first thing to do is find a number that evenly divides into all three. That is, a number that divides evenly into 20, 25, and 40. It seems clear that the number 5 will do the job. This is because

Pencils:

20

÷

5

=

4

Erasers:

25

÷

5

=

5

Paper clips:

40

÷

5=8

The answer flows freely from this realization. Justin can put 4 pencils, 5 erasers, and 8 paperclips into 5 different bags. If he hands out the bags, 5 different recipients will have the same things in each bag.

Step-by-step explanation:

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step-by-step explanation:

because i said it is

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~