The follovwing two-way table shows the distribution of a random sample of travelers and their preferences for
accommodations and method of travel.
Suppose a traveler is selected from this sample at
random. Let event A= home sharing and event B = fly.
Are events A and B independent?
Method of Travel
O No, P(A) = P(AJB).
O No, P(A) P(B|A).
O Yes, PA) = P(A|B).
O Yes, PA) P(BIA).
Drive
Fly
Total
Home
Sharing
16
20
Hotel
64
16
80
Total
80
20
100

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation:

the given growth  function for the length of the fish (cm) is

f(m) = 5(1.07)m = 5.35m

where 

m = months

at the end of the study, the length is 9.19 cm. the  time for conducting the study is determined as

5.35m = 9.19

m = 1.7178 months

part a.

the study was performed over a time period  of about 1.72 months. therefore  the domain for  plotting the function is 0 < = m < = 1.72.

note:

if growth  continues at this rate for up to m months, then the domain would be 0< =m< =m.

part b.

the growth function is a linear function.

when m=0, f=0.

therefore the initial growth is zero, which represents the y-intercept.

part c.

assume that the growth function is valid for 0< =m< =9.

the average rate of change of the function is the slope of the linear function, which is 5.35 cm/month.

step-by-step explanation:

which statement is true about the local minimum of the graphed function?

over the interval [–4, –2], the local minimum is 0.

over the interval [–2, –1], the local minimum is 25.

over the interval [–1, 4], the local minimum is 0.

over the interval [4, 7], the local minimum is -7.

the formula for converting absorbance to transmittance goes as:

a = log (1/t)  a = 2 - log(%t)  10^a = 1/t  t = 10^-a  %t = 100(10^-a)

so at the given value of a,   a = 1.5

%t = 100(10^-1.5)

%t = 3.16%