Х = 2y + 3
х = 3y – 4

{x,y}={−1,1}

Step-by-step explanation:

// Solve equation [2] for the variable  x

 [2]    x = 3y - 4

// Plug this in for variable  x  in equation [1]

  [1]    (3y-4) - 2y = -3

  [1]    y = 1

// Solve equation [1] for the variable  y

  [1]    y = 1

// By now we know this much :

   x = 3y-4

   y = 1

// Use the  y  value to solve for  x

   x = 3(1)-4 = -1

Step-by-step explanation:

x=2y+3

Xmin:

-10

Xmax:

10

Ymin:

-10

Ymax:

10

х = 3y – 4

Xmin:

-10

Xmax:

10

Ymin:

-10

Ymax:

10

sorry, i can't understand your question. will later if you describe more clearly!

: )

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