In a certain Algebra 2 class of 29 students, 17 of them play basketball and 6 of them play baseball. There are 8 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

Step-by-step explanation:

Let's take a look at the diagram of the situation:

i can't put the diagram here sorry

Thereby, the probability that a student chosen randomly from the class plays both basketball and baseball is:

or %

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4 + 5 7/9= 9 7/9

step-by-step explanation:

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.