Factor the difference of cubes.
x^3– 27=
A(x - 3)(x² + 3x + 9) = 0
B (x + 4)(x² + 3x +9...
Mathematics, 10.12.2020 18:20, Franklyn3220
Factor the difference of cubes.
x^3– 27=
A(x - 3)(x² + 3x + 9) = 0
B (x + 4)(x² + 3x +9) = 0
C(x - 3)(2.x2 + 3x + 9) = 0
D(X- 3)x² + 3.8 + 7) = 0
Answers: 2
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