The westbound bus headed for a town at a speed that was 40 kilometers per hour slower than the speed of a car traveling eastbound towards the town. The speed of the car was 120 kilometers per hour. Though both vehicles spent the same time traveling, the car traveled 20 kilometers more than the bus. How long did each of the vehicles travel?

The bus =40 kilometers

The car = 60km

Step-by-step explanation:

step one:

given

The speed of the car was 120  kilometers per hour

The speed of the bus is 40 kilometers per hour slower than the speed of a car

hence the speed of the bus is = 120-40 = 80 kilometers per hour

Required

The distance traveled

we are told that they spent the same amount of time.

let the distance covered by the bus be x  kilometers

so the distance covered by the car = (20+x)   kilometers

Step two:

from

v=d/t

time= d/v

time taken by the car

= 20+x/1201

time taken by the bus

= x/802

equate both equations

20+x/120=x/80

cross multiply

120x=80(20+x)

120x=1600+80x

120x-80x=1600

40x=1600

divide both sides by 40

x=40 kilometers

The bus travels 40 kilometers

The car travels 20+40= 60km

146%

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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