A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, . y=-16x^2+261x+130

Step-by-step explanation:

Given the maximum height of the rocket modelled by the expression

y=-16x^2+261x+130

The rocket velocity at its maximum height is zero.

v(x) = dy/dx = 0

dy/dx = -32x + 261

0 = -32x + 261

32x = 261

x = 261/32

x= 8.156secs

Substitute the time into the given expression'

y=-16(8.16)^2+261(8.16)+130

y = -1,064.88 + 2,129.76 + 130

y = 1194.88

(x+3)(x+7)

step-by-step explanation:

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.