Review the graph of piecewise function g(x). On a coordinate plane, a curve approaches the x-axis in quadrant 2 and increases to approaches x = negative 3. A curve starts at closed circle (negative 3, 0) and curves down and approaches y = negative 2.4 in quadrants 3 and 4.

What are the one-sided limits around the discontinuity shown in the graph?

Limit of g (x) = 0 as x approaches negative 3 minus. Limit of g (x) D N E as x approaches negative 3 plus.
Limit of g (x) D N E as x approaches negative 3 minus. Limit of g (x) = 0 as x approaches negative 3 plus.
Limit of g (x) = 0 as x approaches negative 3 minus. Limit of g (x) = negative 2.5 as x approaches negative 3 plus.
Limit of g (x) = negative 2.5 as x approaches negative 3 minus. Limit of g (x) = 0 as x approaches negative 3 plus.

step-by-step explanation:

see if this :

the answer will be b x² +x-1

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

explanation:

step-by-step explanation: