EMERGENCY TEST CLOSES SOON AND IM BARELY DONEplease do part 1 and 2 An object is projected into the air. The height of the object after t seconds is modeled by the function in the graph. Time, t, is measured in seconds and height, h(t), is measured in feet.
PART A: Which of the following statements are TRUE? Select all that apply.

A.
The object is launched from the ground.

B.
The flight is symmetric about the line t = 10.

C.
The object reaches a maximum height of 12 feet.

D.
The object is flying in the air during the interval 0 < t < 25.93.

E.
The object reaches its maximum height after 12 seconds of flight.

PART B: The table models the flight of the object.
Timothy said that h(4) < h(20). Do you agree or disagree with Timothy? Explain.
(1 image part a, 2 image part b)

Part A: Options D and E

Part B: Disagree

Step-by-step explanation:

Part A:

From the graph attached,

Option A

The object is launched from the ground.

False.

Since, the object is launched from the 5 feet above the ground.

Option B

The flight is symmetric about the line t = 10

False.

Since, the flight is symmetric about the line t = 12

Option C

The object reaches a maximum height of 12 feet.

False.

At t = 12 seconds maximum height of the object = 19.4 feet

Option D

The object is flying in the air during the interval 0 < t < 25.93

True.

Option E

The object reaches its maximum height after 12 seconds of flight.

True.

After 12 seconds object is at the maximum height 19.4 feet.

Therefore, Options D and E are the correct options.

Part B:

From the table attached,

h(4) = 13

h(20) = 13

At t = 4 and 13 seconds height of the object is same.

h(4) = h(20)

But Timothy said h(4) < h(20)

Therefore, disagree with the statement of Timothy.

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )