Write an equation for a line that is parallel to y + 5 = 3(x - 1) and goes through the point (3,-4)

The  equation for a line that is parallel to y + 5 = 3(x - 1) and goes through the point (3,-4) will be:

Step-by-step explanation:

Given the equation

y + 5 = 3(x - 1)

Writing in the slope-intercept form

y=mx+b

where m is the slope and b is the y-intercept

y = 3(x-1) -5

y  = 3x-3-5

y = 3x - 8

Thus, the slope = m = 3

We know that the parallel lines have equal slopes.

So, the slope of a parallel line is also 3

Using the point-slope form of the line equation

substituting the values m = 3 and the point (3, -4)

y-(-4)=3(x-3)

y+4 = 3x-9

y = 3x-9-4

y = 3x-13

Thus, the  equation for a line that is parallel to y + 5 = 3(x - 1) and goes through the point (3,-4) will be:

  21.3

step-by-step explanation:

multiplying the given equation by c/sin(25°), we get

  c = 9/sin(25°) ≈ 21.2958 ≈ 21.3

we assume "c" is the length of ab, the side opposite angle c in triangle abc.