![A=\left[\begin{array}{cc}1&2\\4&5\end{array}\right] \\\\B= \left[\begin{array}{cc}2&1\\8&5\end{array}\right]](/tpl/images/0966/4224/ddf29.png)
![AB= \left[\begin{array}{cc}1&2\\4&5\end{array}\right] \times \left[\begin{array}{cc}2&1\\8&5\end{array}\right]](/tpl/images/0966/4224/4b717.png)
![= \left[\begin{array}{cc}2+16 &1+10\\8+40&4+25\end{array}\right]\\\\\\= \left[\begin{array}{cc}18 &11\\48&29\end{array}\right]](/tpl/images/0966/4224/0f0e3.png)
![BA= \left[\begin{array}{cc}2&1\\8&5\end{array}\right] \times \left[\begin{array}{cc}1&2\\4&5\end{array}\right]](/tpl/images/0966/4224/c6540.png)
![= \left[\begin{array}{cc}2+4 &4+5\\8+20&16+25\end{array}\right]\\ \\ \\= \left[\begin{array}{cc}6 &9\\28&41\end{array}\right]](/tpl/images/0966/4224/6b15c.png)
it holds the trivially 
use above equations
True or false:
a. A product of two self-adjoint matrices is self-adjoint.
b. If A is self-ad...
Mathematics, 09.12.2020 21:40, genyjoannerubiera
True or false:
a. A product of two self-adjoint matrices is self-adjoint.
b. If A is self-adjoint, then Ak is self-adjoint.
Justify your conclusions
Answers: 3
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