Sin(0)= cos(6) what is the value of 0?

The value of 0 is 84.

Given that,

Based on the above information, the calculation is as follows:

cos θ =sin (90 - θ),

So in the case when θ = 6

So, O will be

O = 90 - θ

O = 90 - 6

O = 84

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We need to find Ο for : sin(Ο)= cos(6)

We know that:

cos θ =sin (90 - θ), so if we call θ = 6 then O will be:

O = 90 - θ

O = 90 - 6

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

its the second choice.

step-by-step explanation:

the elements in the range will be 7 less than the elements in the domain.