Can somebody help me with this question, please? I have no idea how to do this or find the answer. :/ How many ways are there to choose a number from the set {−96, −48, −42, −36, −18, −14, −6, 14} that is divisible by either 6 or 8?

28 different ways

Step-by-step explanation:

This is a combination question. Combination has to do with selection.

Total number of element in the set = 8

Number divisible by 6 or 8 are {-98, -48, -42, -36, -18, -6}

Total number divisible by 6 or 8 is 6

The number of ways we can choose 6 items from 8 is expressed as;

8C6 = 8!/(8-6)!6!

8C6 = 8!/(2)!6!

8C6 = 8*7*6!/2!6!

8C6 = 8*7/2

8C6 = 56/2

8C6 = 28 ways

Hence there are 28 different ways

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

step-by-step explanation:

b and c