Mathematics, 09.12.2020 17:40, jules8022

Find the equation of a parabola with a focus at (3,1) and a directrix at y = 3. Question 5 options:

A)

y = 1∕4(x – 3)2 + 2

B)

y = –1∕4 (x – 3)2 + 3

C)

y = –1∕4 (x – 3)2 + 2

D)

y = 1∕4(x – 3)2 + 3

Answers: 1

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Find the equation of a parabola with a focus at (3,1) and a directrix at y = 3. Question 5 options: A) y = 1∕4(x – 3)2 + 2 B) y = –1∕4 (x – 3)2 + 3 C) y = –1∕4 (x – 3)2 + 2 D) y = 1∕4(x – 3)2 + 3

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Find the equation of a parabola with a focus at (3,1) and a directrix at y = 3. Question 5 options:

A)

y = 1∕4(x – 3)2 + 2

B)

y = –1∕4 (x – 3)2 + 3

C)

y = –1∕4 (x – 3)2 + 2

D)

y = 1∕4(x – 3)2 + 3