Let x denote the average number of hours per week that a student at Happy High School spends doing homework. Suppose the frequency distribution of x is normal (i. E., symmetrical and bell-shaped) with a mean of 3.4 hrs. And a standard deviation of 2.6 hrs. What percentage of the students at Happy High spend an average of less than 6 hours per week doing homework?

0.84134

Step-by-step explanation:

Given that:

Mean = 3.4 hours

Standard deviation (s) = 2.6 hours

Percentage of students that spend less than 6 hours doing homework

P(x < 6)

Using the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (6 - 3.4) / 2.6

Z = 2.6 / 2.6

Z = 1

p(Z < 1) = 0.84134 ( Z probability calculator)

The percentage of the students at Happy High spends an average of less than 6 hours per week doing homework is 0.84134

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

answer: 30

step-by-step explanation: its 30 because im a basketball player and stephen curry hits most of his shots so if you put 30 you might make the shot goodluck