1995. Were 57 million cats as pets in the U. S. By 2003this number was 61 millionWrite a linea model for the number of cats as pets. Then use the model to predict the number of cats as pets in 2015

Cats as pet in 2015 = 6 million

Step-by-step explanation:

Given:

Cats as pet in 1995 = 57 million

Cats as pet in 2003 = 61 million

Find:

Cats as pet in 2015

Computation:

Difference in year = 2003 - 1995

Difference in year = 8 year

Difference in year = 2015 - 2003

Difference in year = 2015 - 2003

Difference in year = 12 year

Difference in number = 61 - 57

Difference in number = 4 million

So,

Cats as pet in 2015 = 4 million x [12/8]

Cats as pet in 2015 = 6 million

b: |12 – x| ≤ 0.25

step-by-step explanation:      

let x be the possible lengths in inches, of the ribbons jaime cut.

we have been given that jaime is cutting strips of ribbon for a project. he tries to cut each piece to be 12 inches long, but sometimes he cuts it too long or too short by as much as 0.25 inch.  

we can represent this information in an inequality as:

by the definition of absolute value function we will get,

upon combining our inequalities we will get,

therefore, the inequality   describes all the possible lengths (x), in inches, of the ribbons jaime cut.

step-by-step explanation: