The perimeter of a rectangle is (8x + 7y) feet, give two possible dimensions of the rectangle please help ??

Two possible dimensions of the rectangle are 4x and 7/2 y.

Step-by-step explanation:

The Perimeter of a Rectangle

It's given the perimeter of a rectangle is

P = 8x + 7y

The formula to calculate the perimeter of a rectangle of dimensions L and W is:

P = 2W + 2L

Equating term by term, we can guess two possible dimensions of the rectangle:

2W = 8x

Dividing by 2:

W = 4x

And also:

2L = 7y

Dividing by 2:

L = 7/2 y

Thus, two possible dimensions of the rectangle are 4x and 7/2 y.

22

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet