What is the probability that a data value in a normal distribution is between a z-score of -1.32 and a z score of 1.32? Round your answer to the nearest
tenth of a percent.
A. 84.3%
B. 82.3%
C. 83.3%
D. 81.3%
Please tell me how to do this in my calculator

The probability that a data value in a normal distribution is between a

z-score of -1.32 and a z score of 1.32 is 81.3%

Option D is correct.

Step-by-step explanation:

We need to find the probability that a data value in a normal distribution is between a  z-score of -1.32 and a z score of 1.32.

We can write it as P(-1.32 < Z < 1.32)

It is equal to :

Looking at z-score tables to find value of z=1.32 and z=-1.32

P(Z<1.32)= 0.90658

P(Z<-1.32) = 0.09342

Putting values and finding answer

So, the probability that a data value in a normal distribution is between a

z-score of -1.32 and a z score of 1.32 is 81.3%

Option D is correct.

256π units²   (answer b)

step-by-step explanation:

the formula for the surface area of a sphere of radius r

is             a = 4πr²

and so, if r = 8 units, then the surface area is:

a = 4π(8 units)² = 256π units²   (answer b)

a) t'(-3, 6) and v'(0, 3)  

step-by-step explanation: